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Skill 3 · Dead reckoningProblem 13007
Two legs from a 1535 fix: where is the 1625 DR?
At 1535 you fix your position 326°T, 2.7 nm from Tern Island tower. You steer 240°T at 4.1 kn until 1600, then 095°T at 9.0 kn until 1625.
Give the 1625 DR position as the true bearing FROM Tern Island tower to the DR, and the distance. Courses are true and speeds are through the water; dead reckoning ignores current and leeway.
Tolerance: 2° and 0.15 nm (or 4 % of the distance).
| 1535 fix | 326°T, 2.7 nm from Tern Island tower |
|---|---|
| Leg 1 | 240°T, 4.1 kn, 1535 to 1600 |
| Leg 2 | 095°T, 9.0 kn, 1600 to 1625 |
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