Dividers:
Skill 3 · Dead reckoningProblem 188005
Two legs from a 1050 fix: where is the 1115 DR?
At 1050 you fix your position 311°T, 2.6 nm from Tern Island tower. You steer 076°T at 8.8 kn until 1100, then 219°T at 5.4 kn until 1115.
Give the 1115 DR position as the true bearing FROM Tern Island tower to the DR, and the distance. Courses are true and speeds are through the water; dead reckoning ignores current and leeway.
Tolerance: 2° and 0.15 nm (or 4 % of the distance).
| 1050 fix | 311°T, 2.6 nm from Tern Island tower |
|---|---|
| Leg 1 | 076°T, 8.8 kn, 1050 to 1100 |
| Leg 2 | 219°T, 5.4 kn, 1100 to 1115 |
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