Dividers:
Skill 3 · Dead reckoningProblem 189005
Two legs from a 1515 fix: where is the 1540 DR?
At 1515 you fix your position 293°T, 3.6 nm from Tern Island tower. You steer 279°T at 4.9 kn until 1525, then 120°T at 5.2 kn until 1540.
Give the 1540 DR position as the true bearing FROM Tern Island tower to the DR, and the distance. Courses are true and speeds are through the water; dead reckoning ignores current and leeway.
Tolerance: 2° and 0.15 nm (or 4 % of the distance).
| 1515 fix | 293°T, 3.6 nm from Tern Island tower |
|---|---|
| Leg 1 | 279°T, 4.9 kn, 1515 to 1525 |
| Leg 2 | 120°T, 5.2 kn, 1525 to 1540 |
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