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Skill 3 · Dead reckoningProblem 342007
Two legs from a 1540 fix: where is the 1635 DR?
At 1540 you fix your position 261°T, 2.7 nm from Tern Island tower. You steer 356°T at 4.3 kn until 1615, then 097°T at 5.9 kn until 1635.
Give the 1635 DR position as the true bearing FROM Tern Island tower to the DR, and the distance. Courses are true and speeds are through the water; dead reckoning ignores current and leeway.
Tolerance: 2° and 0.15 nm (or 4 % of the distance).
| 1540 fix | 261°T, 2.7 nm from Tern Island tower |
|---|---|
| Leg 1 | 356°T, 4.3 kn, 1540 to 1615 |
| Leg 2 | 097°T, 5.9 kn, 1615 to 1635 |
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