Dividers:
Skill 3 · Dead reckoningProblem 415006
Two legs from a 1015 fix: where is the 1125 DR?
At 1015 you fix your position 259°T, 2.9 nm from Tern Island tower. You steer 327°T at 4.9 kn until 1055, then 146°T at 6.7 kn until 1125.
Give the 1125 DR position as the true bearing FROM Tern Island tower to the DR, and the distance. Courses are true and speeds are through the water; dead reckoning ignores current and leeway.
Tolerance: 2° and 0.15 nm (or 4 % of the distance).
| 1015 fix | 259°T, 2.9 nm from Tern Island tower |
|---|---|
| Leg 1 | 327°T, 4.9 kn, 1015 to 1055 |
| Leg 2 | 146°T, 6.7 kn, 1055 to 1125 |
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