Dividers:
Skill 3 · Dead reckoningProblem 52004
Two legs from a 1525 fix: where is the 1630 DR?
At 1525 you fix your position 356°T, 2.6 nm from Mill stack. You steer 120°T at 4.9 kn until 1605, then 309°T at 6.5 kn until 1630.
Give the 1630 DR position as the true bearing FROM Mill stack to the DR, and the distance. Courses are true and speeds are through the water; dead reckoning ignores current and leeway.
Tolerance: 2° and 0.15 nm (or 4 % of the distance).
| 1525 fix | 356°T, 2.6 nm from Mill stack |
|---|---|
| Leg 1 | 120°T, 4.9 kn, 1525 to 1605 |
| Leg 2 | 309°T, 6.5 kn, 1605 to 1630 |
Free skill. Plot Pass $1.95/month or $19.50/year · Free during preview: all eight skills, worksheets with answer keys, a 5,000-attempt Plot Log and CSV.