Dividers:
Skill 3 · Dead reckoningProblem 522006
Two legs from a 1440 fix: where is the 1515 DR?
At 1440 you fix your position 324°T, 1.9 nm from Mill stack. You steer 302°T at 9.3 kn until 1450, then 086°T at 5.0 kn until 1515.
Give the 1515 DR position as the true bearing FROM Mill stack to the DR, and the distance. Courses are true and speeds are through the water; dead reckoning ignores current and leeway.
Tolerance: 2° and 0.15 nm (or 4 % of the distance).
| 1440 fix | 324°T, 1.9 nm from Mill stack |
|---|---|
| Leg 1 | 302°T, 9.3 kn, 1440 to 1450 |
| Leg 2 | 086°T, 5.0 kn, 1450 to 1515 |
Free skill. Plot Pass $1.95/month or $19.50/year · Free during preview: all eight skills, worksheets with answer keys, a 5,000-attempt Plot Log and CSV.