Dividers:
Skill 3 · Dead reckoningProblem 541006
Two legs from a 1040 fix: where is the 1125 DR?
At 1040 you fix your position 253°T, 1.9 nm from Tern Island tower. You steer 172°T at 5.9 kn until 1115, then 222°T at 5.7 kn until 1125.
Give the 1125 DR position as the true bearing FROM Mill stack to the DR, and the distance. Courses are true and speeds are through the water; dead reckoning ignores current and leeway.
Tolerance: 2° and 0.15 nm (or 4 % of the distance).
| 1040 fix | 253°T, 1.9 nm from Tern Island tower |
|---|---|
| Leg 1 | 172°T, 5.9 kn, 1040 to 1115 |
| Leg 2 | 222°T, 5.7 kn, 1115 to 1125 |
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