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Skill 3 · Dead reckoningProblem 590003
Two legs from a 0940 fix: where is the 1025 DR?
At 0940 you fix your position 338°T, 2.7 nm from Tern Island tower. You steer 228°T at 5.0 kn until 0955, then 083°T at 9.0 kn until 1025.
Give the 1025 DR position as the true bearing FROM Tern Island tower to the DR, and the distance. Courses are true and speeds are through the water; dead reckoning ignores current and leeway.
Tolerance: 2° and 0.15 nm (or 4 % of the distance).
| 0940 fix | 338°T, 2.7 nm from Tern Island tower |
|---|---|
| Leg 1 | 228°T, 5.0 kn, 0940 to 0955 |
| Leg 2 | 083°T, 9.0 kn, 0955 to 1025 |
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