Dividers:
Skill 3 · Dead reckoningProblem 732004
Two legs from a 1535 fix: where is the 1625 DR?
At 1535 you fix your position 295°T, 3.0 nm from Tern Island tower. You steer 146°T at 5.1 kn until 1610, then 219°T at 6.5 kn until 1625.
Give the 1625 DR position as the true bearing FROM Tern Island tower to the DR, and the distance. Courses are true and speeds are through the water; dead reckoning ignores current and leeway.
Tolerance: 2° and 0.15 nm (or 4 % of the distance).
| 1535 fix | 295°T, 3.0 nm from Tern Island tower |
|---|---|
| Leg 1 | 146°T, 5.1 kn, 1535 to 1610 |
| Leg 2 | 219°T, 6.5 kn, 1610 to 1625 |
Free skill. Plot Pass $1.95/month or $19.50/year · Free during preview: all eight skills, worksheets with answer keys, a 5,000-attempt Plot Log and CSV.